Math Genius: Symmetric nodes and interpolation error

Original Source Link

Given the nodes $x_0<…<x_n$ that are symmetric, $x_{n-j}=x_j$, how do I show that for $xin text{conv}{x_j}$

I get that I can use the symmetry $x_{n-j}=x_j Leftrightarrow x-x_{n-j}=x-x_j$. Then the book does the step where I do not understand the last equality only:

How do I get this last inquality?

Tagged : / /

Leave a Reply

Your email address will not be published. Required fields are marked *